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GCSE probability practice and worked examples

Describe chances as fractions, decimals or percentages and check that possible outcomes account for the whole event.

Foundation and Higher · Useful for students building fluency and applying the method in GCSE questions.

Core pathway. Core GCSE methods are useful across Foundation and Higher. Start with the core examples and questions.

Higher extension. More demanding selections are marked Higher extension: practice questions 6, 8. Use these after the core work, following your teacher’s guidance.

3 worked examples and 8 original practice questions · Allow 25–40 minutes · Read online or print. Higher extensions are labelled. No account or email needed.

Learn the methodTry the questions

Printing includes the method, examples and space for working, followed by a separate answer section.

A useful approach

  1. For equally likely outcomes, divide the number of favourable outcomes by the total.
  2. Probabilities of all mutually exclusive, exhaustive outcomes sum to 1.
  3. On a tree, multiply along a branch route and add separate routes that meet the event. Check whether replacement changes the second probability.

A mistake to watch for

Adding probabilities works for mutually exclusive alternatives. Multiplying is used for a sequence, with any dependence reflected in the branch values.

Learn each method, then practise it

Read each line of working and explain why it follows from the previous line.

Equally likely outcomes

Divide favourable outcomes by the total number of equally likely outcomes. For the opposite event, subtract its probability from 1.

Worked example 1

Probability · Core GCSE skill · No calculator · 1 marks

A fair six-sided dice is rolled once.

Write down the probability that the dice lands on a number less than 3.

  1. The numbers less than 3 are 1 and 2, so there are 2 successful outcomes out of 6 equally likely outcomes.
  2. P(less than 3) = =
Answer:
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Now practise this method: Question 1 · Question 2

A complete set of outcomes

Mutually exclusive and exhaustive outcomes have probabilities totalling 1. Use frequencies to estimate a probability when the question gives experimental results. Relative frequency is the observed count divided by the number of trials. An estimated future count is probability multiplied by the number of trials. When the remaining outcomes are in a ratio, share the remaining probability using those ratio parts.

Worked example 2

Probability · Core GCSE skill · No calculator · 2 marks

A spinner can land on red, blue, green or yellow.

The table shows the probabilities for three of the colours.

Colourredbluegreenyellow
Probability0.20.350.1

Work out the probability that the spinner lands on yellow.

  1. The four probabilities must add up to 1.
  2. 0.2 + 0.35 + 0.1 = 0.65.
  3. P(yellow) = 1 - 0.65 = 0.35
Answer: 0.35
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Now practise this method: Question 3 · Question 4 · Question 5

Two-stage events

Multiply along each route in a probability tree and add alternative routes. For independent events the second probability does not change; without replacement it may change.

Worked example 3

Probability Trees · Core GCSE skill · Calculator allowed · 3 marks

A bag contains 3 red counters and 7 blue counters.

Kira takes a counter at random, notes its colour and puts it back.

She then takes a second counter at random.

  1. Complete the probability tree diagram for the two picks.
  2. Work out the probability that both counters are blue.
First counterSecond counterRedRedBlueBlueRedBlue
Diagram for Probability Trees. The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. A bag contains 3 red counters and 7 blue counters. Kira takes a counter at random, notes its colour and puts it back. She then takes a second counter at random. Complete the probability tree diagram for the two picks. Work out the probability that both counters are blue. Use the labelled information; do not estimate measurements from the sketch.

  1. P(red) = = 0.3 and P(blue) = = 0.7.
  2. The counter is replaced, so the second pick has the same probabilities.
  3. P(both blue) = 0.7 × 0.7 = 0.49
Answer: (a) P(red) = 0.3 and P(blue) = 0.7 on every pair of branches   (b) 0.49
First counterSecond counter0.3Red0.3Red0.7Blue0.7Blue0.3Red0.7Blue
Model diagram: compare the plotted points or labelled working with your method.
Read a text description of this diagram

Worked diagram. A bag contains 3 red counters and 7 blue counters. Kira takes a counter at random, notes its colour and puts it back. She then takes a second counter at random. Complete the probability tree diagram for the two picks. Work out the probability that both counters are blue. Model working: P(red) = ( 3 ) divided by ( 10 ) = 0.3 and P(blue) = ( 7 ) divided by ( 10 ) = 0.7. The counter is replaced, so the second pick has the same probabilities. P(both blue) = 0.7 × 0.7 = 0.49

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Now practise this method: Question 6 · Question 7 · Question 8

Your practice questions

Write your working on paper. Marks indicate how much working to show; these questions are self-marked and do not change saved practice results. Use squared paper for drawing questions.

Question 3

Probability · Core GCSE skill · Calculator allowed · 2 marks

Amy and Ben each spin the same spinner and record how many times it lands on red.

Number of spinsNumber of reds
Amy5018
Ben15042

Using all of the results, work out the best estimate for the probability that the spinner lands on red.

Check answer and working for question 3

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Question 5

Probability · Core GCSE skill · No calculator · 3 marks

A bag contains only red, blue and green counters.

of the counters are green.

The rest of the counters are red and blue in the ratio red : blue = 3 : 2.

A counter is taken from the bag at random.

Work out the probability that the counter is blue.

Check answer and working for question 5

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Question 7

Probability Trees · Core GCSE skill · Calculator allowed · 4 marks

The probability that Jon's bus is on time on any day is 0.9.

Whether the bus is on time on one day is independent of any other day.

Jon catches the bus on Monday and on Tuesday.

  1. Complete the probability tree diagram.
  2. Work out the probability that the bus is on time on both days.
MondayTuesday0.9On timeOn timeLateLateOn timeLate
Diagram for Probability Trees. The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. The probability that Jon's bus is on time on any day is 0.9. Whether the bus is on time on one day is independent of any other day. Jon catches the bus on Monday and on Tuesday. Complete the probability tree diagram. Work out the probability that the bus is on time on both days. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 7

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Worked answers: Probability

Compare the reasoning as well as the final answer. Another correct method is valid. If a step is unclear, revisit an example before trying a similar question.

Answer 1

Show answer and working for question 1
  1. The number of tickets that are not Priya's is 400 - 12 = 388.
  2. P(Priya does not win) = =
Answer:
Back to question 1

Answer 2

Show answer and working for question 2
  1. Total number of counters = 4 + 7 + 9 = 20.
  2. Counters that are not green = 7 + 9 = 16.
  3. P(not green) = =
Answer:
Back to question 2

Answer 3

Show answer and working for question 3
  1. Combining both sets of results gives the largest number of trials, so it gives the best estimate.
  2. Total reds = 18 + 42 = 60, total spins = 50 + 150 = 200.
  3. Best estimate for P(red) = = = 0.3
Answer:
Back to question 3

Answer 4

Show answer and working for question 4
  1. Expected number of late days = probability × number of days.
  2. 0.15 × 40 = 6
Answer: 6
Back to question 4

Answer 5

Show answer and working for question 5
  1. The fraction of counters that are red or blue = 1 - = .
  2. Blue counters are 2 parts out of 5, so the blue fraction of the rest = .
  3. P(blue) = × = =
Answer:
Back to question 5

Answer 6

Show answer and working for question 6
  1. P(wins both games) = × = .
  2. Losing at least one game is the opposite of winning both.
  3. P(loses at least one) = 1 - =
Answer:
Back to question 6

Answer 7

Show answer and working for question 7
  1. Each pair of branches sums to 1, so P(late) = 1 - 0.9 = 0.1.
  2. P(on time both days) = 0.9 × 0.9 = 0.81
Answer: (a) P(late) = 0.1 on each pair of branches, P(on time) = 0.9 on the second day branches   (b) 0.81
MondayTuesday0.9On time0.9On time0.1Late0.1Late0.9On time0.1Late
Model diagram: compare the plotted points or labelled working with your method.
Read a text description of this diagram

Worked diagram. The probability that Jon's bus is on time on any day is 0.9. Whether the bus is on time on one day is independent of any other day. Jon catches the bus on Monday and on Tuesday. Complete the probability tree diagram. Work out the probability that the bus is on time on both days. Model working: Each pair of branches sums to 1, so P(late) = 1 - 0.9 = 0.1. P(on time both days) = 0.9 × 0.9 = 0.81

Back to question 7

Answer 8

Show answer and working for question 8
  1. P(Cara passes and Dan fails) = 0.6 × 0.25 = 0.15.
  2. P(Cara fails and Dan passes) = 0.4 × 0.75 = 0.3.
  3. P(exactly one passes) = 0.15 + 0.3 = 0.45
Answer: 0.45
Back to question 8

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