Describe chances as fractions, decimals or percentages and check that possible outcomes account for the whole event.
Foundation and Higher · Useful for students building fluency and applying the method in GCSE questions.
Core pathway. Core GCSE methods are useful across Foundation and Higher. Start with the core examples and questions.
Higher extension. More demanding selections are marked Higher extension: practice questions 6, 8. Use these after the core work, following your teacher’s guidance.
3 worked examples and 8 original practice questions · Allow 25–40 minutes · Read online or print. Higher extensions are labelled. No account or email needed.
Printing includes the method, examples and space for working, followed by a separate answer section.
A useful approach
For equally likely outcomes, divide the number of favourable outcomes by the total.
Probabilities of all mutually exclusive, exhaustive outcomes sum to 1.
On a tree, multiply along a branch route and add separate routes that meet the event. Check whether replacement changes the second probability.
A mistake to watch for
Adding probabilities works for mutually exclusive alternatives. Multiplying is used for a sequence, with any dependence reflected in the branch values.
Learn each method, then practise it
Read each line of working and explain why it follows from the previous line.
Equally likely outcomes
Divide favourable outcomes by the total number of equally likely outcomes. For the opposite event, subtract its probability from 1.
Worked example 1
Probability · Core GCSE skill · No calculator · 1 marks
A fair six-sided dice is rolled once.
Write down the probability that the dice lands on a number less than 3.
The numbers less than 3 are 1 and 2, so there are 2 successful outcomes out of 6 equally likely outcomes.
Mutually exclusive and exhaustive outcomes have probabilities totalling 1. Use frequencies to estimate a probability when the question gives experimental results. Relative frequency is the observed count divided by the number of trials. An estimated future count is probability multiplied by the number of trials. When the remaining outcomes are in a ratio, share the remaining probability using those ratio parts.
Worked example 2
Probability · Core GCSE skill · No calculator · 2 marks
A spinner can land on red, blue, green or yellow.
The table shows the probabilities for three of the colours.
Colour
red
blue
green
yellow
Probability
0.2
0.35
0.1
Work out the probability that the spinner lands on yellow.
Multiply along each route in a probability tree and add alternative routes. For independent events the second probability does not change; without replacement it may change.
Worked example 3
Probability Trees · Core GCSE skill · Calculator allowed · 3 marks
A bag contains 3 red counters and 7 blue counters.
Kira takes a counter at random, notes its colour and puts it back.
She then takes a second counter at random.
Complete the probability tree diagram for the two picks.
Work out the probability that both counters are blue.
Diagram for Probability Trees. The question states the required measurements and relationships.Read a text description of this diagram
Given diagram. A bag contains 3 red counters and 7 blue counters. Kira takes a counter at random, notes its colour and puts it back. She then takes a second counter at random. Complete the probability tree diagram for the two picks. Work out the probability that both counters are blue. Use the labelled information; do not estimate measurements from the sketch.
P(red) = 310 = 0.3 and P(blue) = 710 = 0.7.
The counter is replaced, so the second pick has the same probabilities.
P(both blue) = 0.7 × 0.7 = 0.49
Answer: (a) P(red) = 0.3 and P(blue) = 0.7 on every pair of branches (b) 0.49
Model diagram: compare the plotted points or labelled working with your method.Read a text description of this diagram
Worked diagram. A bag contains 3 red counters and 7 blue counters. Kira takes a counter at random, notes its colour and puts it back. She then takes a second counter at random. Complete the probability tree diagram for the two picks. Work out the probability that both counters are blue. Model working: P(red) = ( 3 ) divided by ( 10 ) = 0.3 and P(blue) = ( 7 ) divided by ( 10 ) = 0.7. The counter is replaced, so the second pick has the same probabilities. P(both blue) = 0.7 × 0.7 = 0.49
Write your working on paper. Marks indicate how much working to show; these questions are self-marked and do not change saved practice results. Use squared paper for drawing questions.
Question 1
Probability · Core GCSE skill · Calculator allowed · 2 marks
Priya buys 12 tickets in a school raffle.
A total of 400 tickets are sold.
One ticket is picked at random to win the prize.
Work out the probability that Priya does not win the prize.
Probability Trees · Core GCSE skill · Calculator allowed · 4 marks
The probability that Jon's bus is on time on any day is 0.9.
Whether the bus is on time on one day is independent of any other day.
Jon catches the bus on Monday and on Tuesday.
Complete the probability tree diagram.
Work out the probability that the bus is on time on both days.
Diagram for Probability Trees. The question states the required measurements and relationships.Read a text description of this diagram
Given diagram. The probability that Jon's bus is on time on any day is 0.9. Whether the bus is on time on one day is independent of any other day. Jon catches the bus on Monday and on Tuesday. Complete the probability tree diagram. Work out the probability that the bus is on time on both days. Use the labelled information; do not estimate measurements from the sketch.
Compare the reasoning as well as the final answer. Another correct method is valid. If a step is unclear, revisit an example before trying a similar question.
Answer 1
Show answer and working for question 1
The number of tickets that are not Priya's is 400 - 12 = 388.
Each pair of branches sums to 1, so P(late) = 1 - 0.9 = 0.1.
P(on time both days) = 0.9 × 0.9 = 0.81
Answer: (a) P(late) = 0.1 on each pair of branches, P(on time) = 0.9 on the second day branches (b) 0.81
Model diagram: compare the plotted points or labelled working with your method.Read a text description of this diagram
Worked diagram. The probability that Jon's bus is on time on any day is 0.9. Whether the bus is on time on one day is independent of any other day. Jon catches the bus on Monday and on Tuesday. Complete the probability tree diagram. Work out the probability that the bus is on time on both days. Model working: Each pair of branches sums to 1, so P(late) = 1 - 0.9 = 0.1. P(on time both days) = 0.9 × 0.9 = 0.81
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