The vectors a and b are given by a = 3−4 and b = −25
Find 2a − 3b, giving your answer in terms of i and j
Find |a|
3 marks
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a) 12i - 23jb) |a| = 5
2
The vector v = 5i − 12j
Find a unit vector in the direction of v
Find the angle between v and the positive i direction.
4 marks
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a)513i - 1213jb) 67.4° (below the i direction)
3
Relative to a fixed origin O, the point A has position vector 2i − j and the point B has position vector −4i + 7j
Find →AB
Find the distance AB
Find the position vector of the midpoint of AB
4 marks
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a) -6i + 8jb) 10c) -i + 3j
4
The vectors p = (k + 2)i + 6j and q = 2i + (k + 3)j, where k is a constant.
Given that p is parallel to q, find the possible values of k.
4 marks
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k = 1 or k = -6
5
The vector c = 2ti + (t − 5)j, where t is a constant.
Given that |c| = √65
find the possible values of t
find, for the positive value of t, a unit vector in the direction of c
5 marks
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a) t = 4 or t = -2b)1√65(8i - j)
6
Relative to a fixed origin O, the points A and B have position vectors
→OA = 3i + j and →OB = −i + 4j
Find the size of angle AOB, giving your answer in degrees to one decimal place.
Find the exact area of triangle OAB
6 marks
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a) 85.6°b)132
7
Relative to a fixed origin O, the points A, B, C and D have position vectors
a = i + 2j, b = 5i + 4j, c = 8i + 10j, d = 2i + 7j
Show that ABCD is a trapezium, giving reasons for your answer.
Find the ratio AB : DC
4 marks
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a) DC = 32AB so AB ∥ DC, and AD is not parallel to BC, so ABCD is a trapeziumb) 2 : 3
8
Relative to a fixed origin O, the point A has position vector 4i − 7j and the point B has position vector 14i + 8j
The point P lies on the line segment AB such that AP : PB = 3 : 2
Find the position vector of P
Find |→OP|, giving your answer as a simplified surd.
4 marks
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a) 10i + 2jb) 2√26
9
In triangle OAB, →OA = a and →OB = b
The point M is the midpoint of OA. The point N lies on AB such that AN : NB = 2 : 1
Find →MN in terms of a and b, giving your answer in its simplest form.
The point P is such that →OP = 2b
Show that M, N and P lie on a straight line.
Find the ratio MN : NP
6 marks
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a) MN = -16a + 23bb) MP = 3MN, a multiple with the common point M, so M, N and P are collinearc) 1 : 2
10
A park is modelled as a quadrilateral OPQR. Relative to the point O, the corners have position vectors
→OP = 6i, →OQ = 10i + 9j, →OR = 8i + 18j
where i and j are unit vectors due east and due north and each unit represents 10 metres.
Show that the side PQ is parallel to the side OR
A straight path runs from O to Q. Find the length of the path in metres.
Find the size of angle OPQ
Give one limitation of the model.
8 marks
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a) PQ = 4i + 9j and OR = 2PQ, so they are parallelb) 135 m (3 s.f.)c) 114.0°d) e.g. the edges of the park will not be exactly straight lines, or the ground is not flat
11
Relative to a fixed origin O, the points A, B and C have position vectors
i + 2j, 4i + 6j and pi − 3j
respectively, where p is a constant. Given that angle ABC = 90°
use Pythagoras' theorem to find the value of p
find the area of triangle ABC
The point D is such that ABCD is a rectangle. Find the position vector of D
7 marks
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a) p = 16b) 37.5c) 13i - 7j
12
In triangle OAB, →OA = a and →OB = b
The point P lies on OA such that OP : PA = 1 : 2 and the point Q is the midpoint of AB. The lines OQ and BP meet at the point X.
Find, in terms of a and b, (i) →OQ (ii) →BP
Using a vector method, find the ratio OX : XQ
Find the ratio BX : XP
8 marks
Show answer
a) OQ = 12a + 12b; BP = 13a - bb) 1 : 1c) 3 : 1
Every question here is original and written by Robinson Tuition. It follows the Edexcel AS specification and suits AQA and OCR AS maths too; this is not an exam-board paper.