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GCSE right-angled trigonometry practice and worked examples

Choose sine, cosine or tangent from the sides involved. Practise finding a missing side and an acute angle, then apply the same ideas in contexts.

Foundation and Higher · Useful near the top of Foundation and for Higher revision. Later questions combine steps.

Core pathway. Core GCSE methods are useful across Foundation and Higher. Start with the core examples and questions.

Higher extension. More demanding selections are marked Higher extension: practice questions 2, 4, 5. Use these after the core work, following your teacher’s guidance.

2 worked examples and 8 original practice questions · Allow 25–40 minutes · Read online or print. Higher extensions are labelled. No account or email needed.

Learn the methodTry the questions

Printing includes the method, examples and space for working, followed by a separate answer section.

A useful approach

  1. Label opposite, adjacent and hypotenuse relative to the angle you are using.
  2. Choose sin = opposite/hypotenuse, cos = adjacent/hypotenuse or tan = opposite/adjacent.
  3. Rearrange before calculating. Use inverse trig for an angle and check your calculator is in degrees.

A mistake to watch for

The opposite and adjacent sides depend on the chosen angle. The hypotenuse is always opposite the right angle.

Learn each method, then practise it

Read each line of working and explain why it follows from the previous line.

Find a missing side

Label opposite, adjacent and hypotenuse relative to the chosen angle. Select sine, cosine or tangent and rearrange before using the calculator in degrees.

Worked example 1

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 2 marks

In triangle ABC, angle ABC = 90° and angle BAC = 34°.

AB = 12 cm.

Work out the length of BC.

Give your answer correct to 3 significant figures.

12 cm34°ABCDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle ABC, angle ABC = 90 degrees and angle BAC = 34 degrees. AB = 12 cm. Work out the length of BC. Give your answer correct to 3 significant figures. Use the labelled information; do not estimate measurements from the sketch.

  1. BC is opposite the 34° angle and AB = 12 cm is adjacent to it, so use tan.
  2. tan 34° = BC ÷ 12.
  3. BC = 12 × tan 34° = 12 × 0.6745... = 8.094... = 8.09 cm (3 sf).
Answer: 8.09 cm
Report a problem with this question

Now practise this method: Question 1 · Question 2 · Question 3 · Question 4 · Question 5 · Question 8

Find an acute angle

Form a ratio from the two known sides, then use the matching inverse trig function. Check that the answer is between 0° and 90°.

Worked example 2

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 2 marks

In triangle DEF, angle DEF = 90°.

DE = 10 cm and EF = 7 cm.

Work out the size of angle FDE.

Give your answer correct to 1 decimal place.

10 cm7 cmDEFDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle DEF, angle DEF = 90 degrees. DE = 10 cm and EF = 7 cm. Work out the size of angle FDE. Give your answer correct to 1 decimal place. Use the labelled information; do not estimate measurements from the sketch.

  1. EF = 7 cm is opposite angle FDE and DE = 10 cm is adjacent to it, so use tan.
  2. tan FDE = 7 ÷ 10 = 0.7.
  3. Angle FDE = tan-1(0.7) = 34.99... = 35.0° (1 dp).
Answer: 35.0°
Report a problem with this question

Now practise this method: Question 6 · Question 7 · Question 8

Your practice questions

Write your working on paper. Marks indicate how much working to show; these questions are self-marked and do not change saved practice results. Use squared paper for drawing questions.

Question 1

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 2 marks

In triangle PQR, angle PQR = 90° and angle PRQ = 52°.

PQ = 9 cm.

Work out the length of PR.

Give your answer correct to 3 significant figures.

9 cm52°PQRDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle PQR, angle PQR = 90 degrees and angle PRQ = 52 degrees. PQ = 9 cm. Work out the length of PR. Give your answer correct to 3 significant figures. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 1

Report a problem with this question

Question 2

SOHCAHTOA (Trigonometry) · Higher extension · Calculator allowed · 2 marks

In triangle RST, angle RST = 90° and angle SRT = 41°.

RT = 20 cm.

Calculate the length of RS.

Give your answer correct to 3 significant figures.

20 cm41°RSTDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle RST, angle RST = 90 degrees and angle SRT = 41 degrees. RT = 20 cm. Calculate the length of RS. Give your answer correct to 3 significant figures. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 2

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Question 3

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 2 marks

A ladder of length 6 m leans against a vertical wall.

The ladder makes an angle of 68° with the horizontal ground.

Work out how far up the wall the ladder reaches.

Give your answer correct to 3 significant figures.

6 m68°ABCWallGroundDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. A ladder of length 6 m leans against a vertical wall. The ladder makes an angle of 68 degrees with the horizontal ground. Work out how far up the wall the ladder reaches. Give your answer correct to 3 significant figures. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 3

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Question 5

SOHCAHTOA (Trigonometry) · Higher extension · Calculator allowed · 3 marks

In triangle ABC, D is the point on AC such that BD is perpendicular to AC.

Angle BAD = 40°, AD = 7 cm and angle BCD = 55°.

Work out the length of BC.

Give your answer correct to 3 significant figures.

7 cm40°55°ADBCDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle ABC, D is the point on AC such that BD is perpendicular to AC. Angle BAD = 40 degrees, AD = 7 cm and angle BCD = 55 degrees. Work out the length of BC. Give your answer correct to 3 significant figures. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 5

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Question 6

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 2 marks

In triangle JKL, angle JKL = 90°.

JK = 5 cm and JL = 13 cm.

Work out the size of angle KJL.

Give your answer correct to 1 decimal place.

5 cm13 cmJKLDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle JKL, angle JKL = 90 degrees. JK = 5 cm and JL = 13 cm. Work out the size of angle KJL. Give your answer correct to 1 decimal place. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 6

Report a problem with this question

Question 7

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 3 marks

In triangle ABC, angle ABC = 90°.

AB = 15 cm and BC = 8 cm.

  1. Work out the size of angle BAC. Give your answer correct to 1 decimal place.
  2. Write down the size of angle BCA, correct to 1 decimal place.
15 cm8 cmABCDiagram NOT accurately drawn
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle ABC, angle ABC = 90 degrees. AB = 15 cm and BC = 8 cm. Work out the size of angle BAC. Give your answer correct to 1 decimal place. Write down the size of angle BCA, correct to 1 decimal place. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 7

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Question 8

SOHCAHTOA (Trigonometry) · Core GCSE skill · Calculator allowed · 4 marks

In triangle ABC, angle ABC = 90° and angle BAC = 27°. AB = 11 cm.

  1. Work out the length of BC. Give your answer correct to 3 significant figures.

In triangle PQR, angle PQR = 90°. PQ = 9 cm and PR = 14 cm.

  1. Work out the size of angle PRQ. Give your answer correct to 1 decimal place.
11 cm27°ABCDiagram NOT accurately drawn(a)9 cm14 cmPQRDiagram NOT accurately drawn(b)
Diagram for SOHCAHTOA (Trigonometry). The question states the required measurements and relationships.
Read a text description of this diagram

Given diagram. In triangle ABC, angle ABC = 90 degrees and angle BAC = 27 degrees. AB = 11 cm. Work out the length of BC. Give your answer correct to 3 significant figures. In triangle PQR, angle PQR = 90 degrees. PQ = 9 cm and PR = 14 cm. Work out the size of angle PRQ. Give your answer correct to 1 decimal place. Use the labelled information; do not estimate measurements from the sketch.

Check answer and working for question 8

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Worked answers: Right-angled trigonometry

Compare the reasoning as well as the final answer. Another correct method is valid. If a step is unclear, revisit an example before trying a similar question.

Answer 1

Show answer and working for question 1
  1. PQ = 9 cm is opposite the 52° angle and PR is the hypotenuse, so use sin.
  2. sin 52° = 9 ÷ PR.
  3. PR = 9 ÷ sin 52° = 9 ÷ 0.7880... = 11.42... = 11.4 cm (3 sf).
Answer: 11.4 cm
Back to question 1

Answer 2

Show answer and working for question 2
  1. RS is adjacent to the 41° angle and RT = 20 cm is the hypotenuse, so use cos.
  2. cos 41° = RS ÷ 20.
  3. RS = 20 × cos 41° = 20 × 0.7547... = 15.09... = 15.1 cm (3 sf).
Answer: 15.1 cm
Back to question 2

Answer 3

Show answer and working for question 3
  1. The height up the wall is opposite the 68° angle and the ladder is the hypotenuse, so use sin.
  2. sin 68° = height ÷ 6.
  3. Height = 6 × sin 68° = 6 × 0.9271... = 5.563... = 5.56 m (3 sf).
Answer: 5.56 m
Back to question 3

Answer 4

Show answer and working for question 4
  1. Multiply both sides by 8: x + 3 = 8 × tan 40°.
  2. 8 × tan 40° = 8 × 0.8390... = 6.712...
  3. x = 6.712... − 3 = 3.712... = 3.71 (3 sf).
Answer: x = 3.71
Back to question 4

Answer 5

Show answer and working for question 5
  1. In right-angled triangle ABD, BD is opposite the 40° angle and AD = 7 cm is adjacent, so BD = 7 × tan 40° = 5.873... cm.
  2. In right-angled triangle BCD, BD is opposite the 55° angle and BC is the hypotenuse, so sin 55° = BD ÷ BC.
  3. BC = 5.873... ÷ sin 55° = 5.873... ÷ 0.8191... = 7.170... = 7.17 cm (3 sf).
Answer: 7.17 cm
Back to question 5

Answer 6

Show answer and working for question 6
  1. JK = 5 cm is adjacent to angle KJL and JL = 13 cm is the hypotenuse, so use cos.
  2. cos KJL = 5 ÷ 13 = 0.3846...
  3. Angle KJL = cos-1() = 67.38... = 67.4° (1 dp).
Answer: 67.4°
Back to question 6

Answer 7

Show answer and working for question 7
  1. a) BC = 8 cm is opposite angle BAC and AB = 15 cm is adjacent, so tan BAC = .
  2. Angle BAC = tan-1() = 28.07... = 28.1° (1 dp).
  3. b) The angles of the triangle sum to 180°, so angle BCA = 180 − 90 − 28.1 = 61.9°.
Answer: (a) 28.1°   (b) 61.9°
Back to question 7

Answer 8

Show answer and working for question 8
  1. a) BC is opposite the 27° angle and AB is adjacent, so BC = 11 × tan 27° = 11 × 0.5095... = 5.604... = 5.60 cm (3 sf).
  2. b) PQ = 9 cm is opposite angle PRQ and PR = 14 cm is the hypotenuse, so sin PRQ = = 0.6428...
  3. Angle PRQ = sin-1() = 40.00... = 40.0° (1 dp).
Answer: (a) 5.60 cm   (b) 40.0°
Back to question 8

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